khó nhìn quá e chỉnh lại đi nha

\(-\frac{3}{5}.\frac{11}{7}+\frac{3}{-5}.\frac{4}{7}+\frac{23}{7}\)

\(=\frac{-3}{5}\left(\frac{11}{7}+\frac{4}{7}\right)+\frac{23}{7}\)

\(=\frac{-3}{5}.\frac{15}{7}+\frac{23}{7}\)

\(=\frac{-9}{7}+\frac{23}{7}=2\)

\(-\frac{5}{7}.\frac{68}{11}+\frac{-5}{7}.\frac{86}{11}+\frac{12}{7}\\ =-\frac{5}{7}.\left(\frac{68}{11}+\frac{86}{11}\right)+\frac{12}{7}\\ =-\frac{5}{7}.\frac{154}{11}+\frac{12}{7}\\ =-\frac{5}{7}.14+\frac{12}{7}\)

\(=-10+\frac{12}{7}\\ =-\frac{70}{10}+\frac{12}{7}=-\frac{58}{7}\)

-5/7.68/11+-5/7.86/11+12/7

=-5/7.(68/11-86/11)+12/7

=-5/7.-18/11+12/7

=90/77+12/7

=90/77+132/77

=222/77

i sorry mk nhầm dấu cộng thành trừ từ bước 2 nếu bạn muốn mk sửa thì nhắn ko thì tự sửa nhé có cách làm rồi

\(\dfrac{16^3.3^{10}+120.6^9}{4^6.3^{12}+6^{11}}=\dfrac{\left(2^4\right)^3.3^{10}+3.5.2^3.\left(2.3\right)^9}{\left(2^2\right)^6.3^{12}+\left(2.3\right)^{11}}\)

\(=\dfrac{2^{12}.3^{10}+3.5.2^3.2^9.3^9}{2^{12}.3^{12}+2^{11}.3^{11}}=\dfrac{2^{12}.3^{10}+5.2^{12}.3^{10}}{2^{12}.3^{12}+2^{11}.3^{11}}\)

\(=\dfrac{2^{12}.3^{10}\left(1+5\right)}{2^{11}.3^{11}.\left(2.3+1\right)}\)\(=\dfrac{2^{12}.3^{10}.6}{2^{11}.3^{11}.7}=\dfrac{2.2}{7}=\dfrac{4}{7}\)

ta có 

(12-12) +(10-9)+(8-7)+(5-4)+(2-1)+(3+11)

=0+1+1+1+1+14=18

12 - 12 +11 + 10 - 9 + 8 - 7 + 5 - 4 + 3 - 2 - 1

= ( 11 - 1 ) + ( 10 -9 ) + ( 8-7) + ( 5 - 4 ) + ( 3-2  ) 

= 10 + 1 + 1 + 1 + 1

=14

12-12+11+10-9+8-7+5-4+3-2-1

=(12-12)+(11+10)-(9-8)-(7-5)-(4-3)-(2+1)

=0+21-1-2-1-3

=21-(1+2+1+3)

=21-7

=14

= -5 / 7 x ( 2 / 11 + 9 / 11) + 12/7

= -5/7 x 1 + 12/7

= -5/7 + 12/7

= 1

b, = ( 9/4 x 105 - 9/4 x 101) : 3/2 - 64 x ( 1/4 - 3/4)

  =  [ 9/4 x ( 105 - 101)] : 3/2 -64 x -1/2

= 9/4 x 4 : 3 /2 - (-32)

= 9 : 3/2 + 32

= 18/3 +32

= 

-5/ 12. (2/11+ 9/11+ (-1)
=-5/ 12. [(11/11+(-1)]

=-5/ 12. (1-1)

= -5/12. 0

=0

\(=\dfrac{-5}{12}\times\left(\dfrac{2}{11}+\dfrac{9}{11}-1\right)\)

\(=\dfrac{-5}{12}\times0=0\)

=−512×0=0

a)

\(\frac{5}{6}-\frac{57}{12}\)

=\(-\frac{47}{12}\)

b)

\(=\frac{3}{7}\left(\frac{9}{11}+\frac{2}{11}\right)\)

\(=\frac{3}{7}.1=\frac{3}{7}\)